If a4 + 1 = $$\left[ {\frac{{{{\text{a}}^2}}}{{{{\text{b}}^2}}}} \right]$$ (4b2 - b4 - 1), then what is the value of a4 + b4?
A. 2
B. 16
C. 32
D. 64
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {a^4} + 1 = \left( {\frac{{{a^2}}}{{{b^2}}}} \right)\left( {4{b^2} - {b^4} - 1} \right) \cr & {\text{take }}a = b = 1 \cr & 1 + 1 = \frac{1}{1}\left( {4 - 1 - 1} \right) \cr & 2 = 2{\text{ satisfied}} \cr & \therefore \,{a^4} + {b^4} = 1 + 1 = 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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