If an ascending gradient of 1 in 50 meets a descending gradient of 1 in 50, the length of summit curve for a stopping sight distance of 80 m will be
A. zero
B. 64m
C. 80m
D. 60m
Answer: Option D
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A. annual average hourly volume
B. annual average daily traffic
C. thirtieth highest hourly volume
D. peak hourly volume of the year
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A. reduces right angled and rear end collisions
B. increases right angled and rear end collisions
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C. 7.5 mm penetration only
D. both 2.5 mm and 5.0 mm penetrations
If aggregate impact value is 20 to 30 percent, then it is classified as
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Ans should be 50m
According to given gradient condition aummit curve will be form..
So for summit curve we have two conditions
1- length of curve > SSD
L= NS^2/4.4
But this condition is not satisfied. So we will use
Second condition i.e.
2- length of curve < SSD
L= 2S- (4.4/N)
And for this condition we have exact answer i.e. equal to 50 meter.
using NS*S/4 formula we are getting L = 64
by gn pbm S=80. So S greater than L
So using the formula L = 2S-4/N
getting the ans is L=60
D is correct ans
Ns/4
NS*S/4 foRMULA SO ANSEWR IS 64
Formula -
(NS²)/4.4