If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what would be the valid subnet address of this host?
A. 172.16.112.0
B. 172.16.0.0
C. 172.16.96.0
D. 172.16.255.0
Answer: Option A
Solution(By Examveda Team)
A /25 mask is 255.255.255.128. Used with a Class B network, the third and fourth octets are used for subnetting with a total of 9 subnet bits, 8 bits in the third octet and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on-which is a value of 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is the next subnet.Join The Discussion
Comments ( 1 )
Related Questions on Subnetting
A. 1 only
B. 2 and 3 only
C. 3 and 4 only
D. None of the above
E. 2 and 5 only
A. 1 and 3
B. 2 and 4
C. 1, 2 and 4
D. 2, 3 and 4
E. 2 and 5 only
A. 1 only
B. 2 only
C. 3 and 4 only
D. 1 and 5 only
E. 2 and 5 only
plz teach me Ethrnet port