If $$\frac{a}{b} = \frac{c}{d} = \frac{e}{f} = 3,$$ then $$\frac{{2{a^2} + 3{c^2} + 4{e^2}}}{{2{b^2} + 3{d^2} + 4{f^2}}}$$ = ?
A. 2
B. 3
C. 4
D. 9
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & \frac{a}{b} = \frac{c}{d} = \frac{e}{f} = \frac{3}{1} \cr & \Rightarrow \frac{{2 \times 9 + 3 \times 9 + 4 \times 9}}{{2 \times 1 + 3 \times 1 + 4 \times 1}} \cr & \Rightarrow \frac{{18 + 27 + 36}}{{2 + 3 + 4}} \cr & \Rightarrow \frac{{81}}{9} \cr & \Rightarrow 9 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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