If $$\frac{{2p}}{{{p^2} - 2p + 1}} = \frac{1}{4}{\text{,}}$$ p ≠ 0 then the value of $$p + \frac{1}{p}\,{\text{is?}}$$
A. 4
B. 5
C. 10
D. 12
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \frac{{2p}}{{{p^2} - 2p + 1}} = \frac{1}{4} \cr & \Rightarrow \frac{{\frac{{2p}}{p}}}{{\frac{{{p^2}}}{p} - \frac{{2p}}{p} + \frac{1}{p}}} = \frac{1}{4} \cr & \Rightarrow \frac{2}{{p + \frac{1}{p} - 2}} = \frac{1}{4} \cr & \Rightarrow p + \frac{1}{p} - 2 = 8 \cr & \Rightarrow p + \frac{1}{p} = 10 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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