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This question belongs to Arithmetic Ability Algebra
Algebra
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If $$\frac{a}{b} = \frac{{25}}{6}{\text{,}}$$   then the value of $$\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}}$$   is?

Answer & Solution
Correct Answer: Option B
$$\eqalign{ & \frac{a}{b} = \frac{{25}}{6} \cr & \frac{{{a^2}}}{{{b^2}}} = \frac{{{{25}^2}}}{{{6^2}}} \cr & \Rightarrow \frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} \cr & \Rightarrow \frac{{{{25}^2} - {6^2}}}{{{{25}^2} + {6^2}}} \cr & \Rightarrow \frac{{625 - 36}}{{625 + 36}} \cr & \Rightarrow \frac{{589}}{{661}} \cr} $$
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