If $$\frac{a}{b} = \frac{{25}}{6}{\text{,}}$$ then the value of $$\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}}$$ is?
A. $$\frac{{589}}{{651}}$$
B. $$\frac{{589}}{{661}}$$
C. $$\frac{{661}}{{589}}$$
D. $$\frac{{625}}{{36}}$$
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & \frac{a}{b} = \frac{{25}}{6} \cr & \frac{{{a^2}}}{{{b^2}}} = \frac{{{{25}^2}}}{{{6^2}}} \cr & \Rightarrow \frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} \cr & \Rightarrow \frac{{{{25}^2} - {6^2}}}{{{{25}^2} + {6^2}}} \cr & \Rightarrow \frac{{625 - 36}}{{625 + 36}} \cr & \Rightarrow \frac{{589}}{{661}} \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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