If $$\frac{x}{y} = \frac{4}{5}{\text{,}}$$ then the value of $$\left( {\frac{4}{7} + \frac{{2y - x}}{{2y + x}}} \right)$$ is?
A. $$\frac{3}{7}$$
B. $${\text{1}}\frac{1}{7}$$
C. 1
D. 2
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \frac{x}{y} = \frac{4}{5} \cr & \frac{4}{7} + \frac{{2y - x}}{{2y + x}} \cr & = \frac{4}{7} + \frac{{y\left( {2 - \frac{x}{y}} \right)}}{{y\left( {2 + \frac{x}{y}} \right)}} \cr & = \frac{4}{7} + \frac{{\left( {2 - \frac{4}{5}} \right)}}{{\left( {2 + \frac{4}{5}} \right)}} \cr & = \frac{4}{7} + \frac{{10 - 4}}{{10 + 4}} \cr & = \frac{4}{7} + \frac{6}{{14}} \cr & {\text{ = }}\frac{{8 + 6}}{{14}} \cr & {\text{ = }}\frac{{14}}{{14}} \cr & {\text{ = 1}} \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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