If $$\frac{{{\text{ }}{x^2} + 1}}{{{x^2}}} = 2{\text{,}}$$ then the value of $$\frac{{x - 1}}{x}$$ is?
A. -2
B. 0
C. 1
D. -1
Answer: Option B
Solution (By Examveda Team)
$$\eqalign{ & {x^2} + \frac{{{\text{ }}1}}{{{x^2}}} = 2 \cr & \Rightarrow {\left( {x - \frac{1}{x}} \right)^2} + 2.x.\frac{1}{x} = 2 \cr & \Rightarrow x - \frac{1}{x} = 2 - 2 \cr & \Rightarrow x - \frac{1}{x} = 0 \cr} $$This Question Belongs to Arithmetic Ability >> Algebra
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