If heat contents of CH4, C2H4 and C3H8 are -17.9, 12.5 and -24.8 kcal/mole respectively, than ΔH for the reaction CH4(g) + C2H4(g) ⇋ C3H8(g) will be __________ Kcal.
A. -19.4
B. -30.2
C. 55.2
D. -55.2
Answer: Option A
Solution (By Examveda Team)
Since the enthalpy change $$=$$ enthalpy or heat content of the products $$–$$ enthalpy or heat content of the reactants $$= -24.8+17.9-12.5 = -19.4.$$This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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