If in the following figure (not to scale), ∠DAB + ∠CBA = 90°, BC = AD, AB = 20 cm, CD = 10 cm
then the area of the quadrilateral ABCD is:
A. 120 cm2
B. 150 cm2
C. 100 cm2
D. 75 cm2
Answer: Option D
Solution (By Examveda Team)
$${\text{Area of ABCD}} = \frac{1}{2} \times 30 \times 5 = 75{\text{ c}}{{\text{m}}^2}$$
This Question Belongs to Arithmetic Ability >> Geometry
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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