If in the given figure, ∠ACB + ∠BAC = 80°, ∠BDE = 35°, ∠BCE = 45°, then the marked angle ∠CED is:
A. 150°
B. 120°
C. 160°
D. 135°
Answer: Option C
Solution (By Examveda Team)
∠BAC + ∠ACB = ∠CBD
80° = ∠CBD
∠CBD = 80°
Let, GH || BD
∠DEH = 35°
∠CGE = 80°
∠CGE + ∠GCE = ∠CEH
80° + 45° = ∠CEH
∠CEH = 125°
∠DEH + ∠CEH = ∠CED
125° + 35° = ∠CED
∠CED = 160°
This Question Belongs to Arithmetic Ability >> Geometry
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