If in ΔPQR, ∠P = 120°, PS ⊥ QR at S and PQ + QS = SR, then the measure of ∠Q is:
A. 20°
B. 50°
C. 40°
D. 30°
Answer: Option C
Solution (By Examveda Team)

Suppose PMQ is isosceles triangle
Since, PQ + QS = SR
Hence MR = a
∠P + ∠Q + ∠R = 180°
120° + 2θ + θ = 180°
θ = 20°
∠Q = 2θ = 40°
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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