If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is
A. -2
B. 3
C. -3
D. 6
Answer: Option B
Solution (By Examveda Team)
(2K - 1) - K = (2K + 1) - (2K - 1)2K - 1 - K = 2
⇒ K = 3
A. -2
B. 3
C. -3
D. 6
Answer: Option B
The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
A. 600
B. 765
C. 640
D. 680
E. 690
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