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If M is the mid-point of the side BC of ΔABC, and the area of ΔABM is 18 cm2, then the area of ΔABC is:
Answer & Solution
Correct Answer:
Option
C

BM : MC= 1 : 1
Area of ΔBMA : Area of ΔAMC
= 1 : 1
↓
18
2 unit → 18 × 2
Area of ΔABC = 36 cm2
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