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If $$N = \frac{{\sqrt 7 - \sqrt 3 }}{{\sqrt 7 + \sqrt 3 }},$$ then what is the value of $$N + \frac{1}{N}?$$
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& N = \frac{{\sqrt 7 - \sqrt 3 }}{{\sqrt 7 + \sqrt 3 }} \cr
& = \frac{{\sqrt 7 - \sqrt 3 }}{{\sqrt 7 + \sqrt 3 }} \times \frac{{\sqrt 7 - \sqrt 3 }}{{\sqrt 7 - \sqrt 3 }} \cr
& = \frac{{7 + 3 - 2\sqrt {21} }}{4} \cr
& = \frac{{10 - 2\sqrt {21} }}{4} \cr
& = \frac{5}{2} - \frac{{\sqrt {21} }}{2} \cr
& {\text{Similarly }}\frac{1}{N} = \frac{5}{2} + \frac{{\sqrt {21} }}{2} \cr
& \therefore N + \frac{1}{N} \cr
& = \frac{5}{2} - \frac{{\sqrt {21} }}{2} + \frac{5}{2} + \frac{{\sqrt {21} }}{2} \cr
& = \frac{5}{2} + \frac{5}{2} \cr
& = 5 \cr} $$
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