If $$\overrightarrow E = \left( {{{\hat a}_x} + j{{\hat a}_y}} \right){e^{ikz - j\omega t}}$$    and $$\overrightarrow H = \left( {\frac{k}{{\omega \mu }}} \right)\left( {{{\hat a}_y} + j{{\hat a}_x}} \right){e^{ikz - j\omega t}},$$       the time averaged poynting vector is

A. null vector

B. $$\left( {\frac{k}{{\omega \mu }}} \right){{\hat a}_z}$$

C. $$\left( {\frac{{2k}}{{\omega \mu }}} \right){{\hat a}_z}$$

D. $$\left( {\frac{k}{{2\omega \mu }}} \right){{\hat a}_z}$$

Answer: Option A