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If p = 124 then the value of root 3 of...

This question belongs to Arithmetic Ability Algebra
Algebra
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If p = 124, then the value of $$\root 3 \of {p\left( {{p^2} + 3p + 3} \right) + 1} = ?$$

Answer & Solution
Correct Answer: Option D
$$\eqalign{ & p = 124 \cr & \root 3 \of {p\left( {{p^2} + 3p + 3} \right) + 1} \cr & = \root 3 \of {{p^3} + 3{p^2} + 3p + 1} \cr & = \root 3 \of {{{\left( {p + 1} \right)}^3}} \cr & = \root 3 \of {{{\left( {125} \right)}^3}} \cr & = 125 \cr} $$
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