If p = 99, then the value of p(p2 + 3p + 3) is?
A. 9999
B. 999999
C. 99999
D. 999
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & \because p = 99 \cr & p\left( {{p^2} + 3p + 3} \right) \cr & = {p^3} + 3{p^2} + 3p + 1 - 1 \cr & = {\left( {p + 1} \right)^3} - 1 \cr & = {\left( {99 + 1} \right)^3} - 1 \cr & = {\left( {100} \right)^3} - 1 \cr & = 1000000 - 1 \cr & = 999999 \cr} $$This Question Belongs to Arithmetic Ability >> Algebra
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