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If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension)

A. $${\left( {\frac{{\sqrt {{{\text{P}}_1}} + \sqrt {{{\text{P}}_2}} }}{2}} \right)^2}$$

B. $${{\text{P}}_1} + {{\text{P}}_2}$$

C. $$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right)$$

D. $$\frac{1}{2}\left( {{{\text{P}}_1} + {{\text{P}}_2}} \right) + {{\text{P}}_{\text{c}}}$$

Answer: Option A


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Comments ( 2 )

  1. Sarveshwer Chandra
    Sarveshwer Chandra :
    4 years ago

    D. [⅟₂ × (P1 + P2)] + Pc

  2. Madhavan Palmani
    Madhavan Palmani :
    4 years ago

    (T1+T2/2) + Tc = T1 + T2 + 2Tc/2.


    Option is D

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