If P(x) = $$\frac{1}{4}$$, P(Y) = $$\frac{1}{3}$$ and $${\text{P}}\left( {{\text{X}} \cap {\text{Y}}} \right) = \frac{1}{{12}},$$ the value of $${\text{P}}\left( {\frac{{\text{Y}}}{{\text{X}}}} \right)$$ is
A. $$\frac{1}{4}$$
B. $$\frac{4}{{25}}$$
C. $$\frac{1}{3}$$
D. $$\frac{{29}}{{50}}$$
Answer: Option C
Related Questions on Probability and Statistics
A coin is tossed 4 times. What is the probability of getting heads exactly 3 times?
A. $$\frac{1}{4}$$
B. $$\frac{3}{8}$$
C. $$\frac{1}{2}$$
D. $$\frac{3}{4}$$
A. 1 and $$\frac{1}{3}$$
B. $$\frac{1}{3}$$ and 1
C. 1 and $$\frac{4}{3}$$
D. $$\frac{1}{3}$$ and $$\frac{4}{3}$$
A. E(XY) = E(X) E(Y)
B. Cov (X, Y) = 0
C. Var (X + Y) = Var (X) + Var (Y)
D. E(X2Y2) = (E(X))2 (E(Y))2

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