If $$\sqrt {1369} + \sqrt {0.0615 + x} $$      = 37.25, the x is equal to ?

A. $${10^{ - 1}}$$

B. $${10^{ - 2}}$$

C. $${10^{ - 3}}$$

D. None of these

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & \Leftrightarrow 37 + \sqrt {0.0615 + x} = 37.25 \cr & \Leftrightarrow \sqrt {0.0615 + x} = 0.25 \cr & \Leftrightarrow 0.0615 + x = {\left( {0.25} \right)^2} = 0.0625 \cr & \Leftrightarrow x = 0.001 \cr & \Leftrightarrow x = \frac{1}{{{{10}^3}}} \cr & \Leftrightarrow x = {10^{ - 3}} \cr} $$