Examveda If $$\sqrt {{3^n}} = 729$$ , then the value of n is ? A. 6B. 8C. 10D. 12Answer: Option D Solution (By Examveda Team) $$\eqalign{ & \Leftrightarrow \sqrt {{3^n}} = 729 \cr & \Leftrightarrow \sqrt {{3^n}} = {3^6} \cr & \Leftrightarrow {\left( {\sqrt {{3^n}} } \right)^2} = {\left( {{3^6}} \right)^2} \cr & \Leftrightarrow {3^n} = {3^{12}} \cr & \Leftrightarrow n = 12 \cr} $$ This Question Belongs to Arithmetic Ability >> Square Root And Cube Root
Solution (By Examveda Team) $$\eqalign{ & \Leftrightarrow \sqrt {{3^n}} = 729 \cr & \Leftrightarrow \sqrt {{3^n}} = {3^6} \cr & \Leftrightarrow {\left( {\sqrt {{3^n}} } \right)^2} = {\left( {{3^6}} \right)^2} \cr & \Leftrightarrow {3^n} = {3^{12}} \cr & \Leftrightarrow n = 12 \cr} $$
What should come in place of both x in the equation $$\frac{x}{{\sqrt {128} }} = \frac{{\sqrt {162} }}{x}$$ A. 12B. 14C. 144D. 196 View Answer
The least perfect square, which is divisible by each of 21, 36 and 66 is: A. 213444B. 214344C. 214434D. 231444 View Answer
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