If $$\sqrt x + \frac{1}{{\sqrt x }} = 2\sqrt 2 ,$$    then $${x^2} + \frac{1}{{{x^2}}}$$  is equal to:

Solution (By Examveda Team)

$$\eqalign{ & \sqrt x + \frac{1}{{\sqrt x }} = 2\sqrt 2 \cr & x + \frac{1}{x} + 2 = 8 \cr & x + \frac{1}{x} = 6 \cr & {x^2} + \frac{1}{{{x^2}}} + 2 = 36 \cr & {x^2} + \frac{1}{{{x^2}}} = 34 \cr} $$