If $$\sqrt x + \frac{1}{{\sqrt x }} = 2\sqrt 2 ,$$ then $${x^2} + \frac{1}{{{x^2}}}$$ is equal to:
A. 34
B. 64
C. 36
D. 32
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & \sqrt x + \frac{1}{{\sqrt x }} = 2\sqrt 2 \cr & x + \frac{1}{x} + 2 = 8 \cr & x + \frac{1}{x} = 6 \cr & {x^2} + \frac{1}{{{x^2}}} + 2 = 36 \cr & {x^2} + \frac{1}{{{x^2}}} = 34 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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