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If $$\sqrt x + \frac{1}{{\sqrt x }} = 2\sqrt 2 ,$$ then $${x^2} + \frac{1}{{{x^2}}}$$ is equal to:
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \sqrt x + \frac{1}{{\sqrt x }} = 2\sqrt 2 \cr
& x + \frac{1}{x} + 2 = 8 \cr
& x + \frac{1}{x} = 6 \cr
& {x^2} + \frac{1}{{{x^2}}} + 2 = 36 \cr
& {x^2} + \frac{1}{{{x^2}}} = 34 \cr} $$
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