If $$\sqrt x = \sqrt 3 - \sqrt 5 {\text{,}}$$ then the value of x2 - 16x + 6 is?
A. 0
B. -2
C. 2
D. 4
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \sqrt x = \sqrt 3 - \sqrt 5 \cr & \left( {{\text{Squaring both sides}}} \right) \cr & \Rightarrow x = 3 + 5 - 2.\sqrt {3.} \sqrt 5 \cr & \Rightarrow x = 8 - 2\sqrt {15} \cr & \Rightarrow x - 8 = - 2\sqrt {15} \cr & \left( {{\text{Squaring both sides}}} \right) \cr & \Rightarrow {x^2} + 64 - 16x = 60 \cr & \Rightarrow {x^2} + 4 - 16x = 0 \cr & \Rightarrow {x^2} + 6 - 16x = 2 \cr & \Rightarrow {x^2} - 16x + 6 = 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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