If T1 and T2 are the tensions on the tight and slack sides of the belt respectively and TC is the centrifugal tension, then initial tension in the belt is equal to
A. T1 - T2 + TC
B. T1 + T2 + TC
C. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2} + {{\text{T}}_{\text{C}}}}}{2}$$
D. $$\frac{{{{\text{T}}_1} + {{\text{T}}_2} + {{\text{T}}_{\text{C}}}}}{2}$$
Answer: Option D
This Question Belongs to Mechanical Engineering >> Machine Design
T0 =(T1+T2/2)+Tc
T1+T2-2Tc correct answer
Correct answer is T1+T2+2Tc/2