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If the a.c. input to a half-wave rectifier is an r.m.s value of $$\frac{{400}}{{\sqrt 2 }}$$   volts, then diode PIV rating is ___________

A. $$\frac{{400}}{{\sqrt 2 }}{\text{ V}}$$

B. 400 V

C. $$400 \times \sqrt 2 {\text{ V}}$$

D. None of the above

Answer: Option B


This Question Belongs to Electrical Engineering >> Semiconductor Diode

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Comments ( 2 )

  1. ABDUL Hasan
    ABDUL Hasan :
    3 years ago

    Option (c) is correct Vrms =Vm/2

  2. Sarita Uniyal
    Sarita Uniyal :
    4 years ago

    for half wave rectifier, PIV rating is Vm i.e peak max voltage
    Here, Vrms= 400/sqrt2
    Vrms=Vm/2 for half wave rectifier, therefore, Vm=800/sqrt2= 400 X( sqrt 2) i.e option (c)

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