If the barometric pressure at a place is 'h' mm of mercury, convert into SI units.
A. $$\frac{{101325}}{{760}} \times h\,N/{m^2}$$
B. $$\frac{{101325}}{{750}} \times h\,N/{m^2}$$
C. $$\frac{{150325}}{{760}} \times h\,N/{m^2}$$
D. $$\frac{{121325}}{{760}} \times h\,N/{m^2}$$
Answer: Option A
This Question Belongs to Mining Engineering >> Mine Ventilation
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