A. $$3.8{\text{ N}}{{\text{V}}^{\frac{1}{2}}}$$
B. $$3.8{\left( {{\text{N}}{{\text{V}}^3}} \right)^{\frac{1}{2}}}$$
C. $$0.38{\left( {{\text{N}}{{\text{V}}^3}} \right)^{\frac{1}{2}}}$$
D. $$0.38{\text{ N}}{{\text{V}}^{\frac{3}{2}}}$$
Answer: Option C
This Question Belongs to Civil Engineering >> Highway Engineering
Highway facilities are designed for
A. annual average hourly volume
B. annual average daily traffic
C. thirtieth highest hourly volume
D. peak hourly volume of the year
The provision of traffic signals at intersections
A. reduces right angled and rear end collisions
B. increases right angled and rear end collisions
C. reduces right angled collisions but may increase rear end collisions
D. reduces rear end collisions but may increase right angled collisions
In CBR test the value of CBR is calculated at
A. 2.5 mm penetration only
B. 5.0 mm penetration only
C. 7.5 mm penetration only
D. both 2.5 mm and 5.0 mm penetrations
If aggregate impact value is 20 to 30 percent, then it is classified as
A. exceptionally strong
B. strong
C. satisfactory for road surfacing
D. unsuitable for road surfacing
To convert radians into degree multiply with 57.29
To convert Kmph into m/s multiple with 100/3600
= 1/3.6 .
Then, take C = 0.6m/s^3
Then finally we get L = 2 (√Nv^3 /C) = 2(√57.29Nv^3) ÷ √( 0.6 × 3.6) = 0.38(Nv^3) ^1/2. Ans. Thank you
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