Examveda

If the electrostatic potential were Igiven by $$\phi = {\phi _0}$$  (x2 + y2 + z2), where $${\phi _0}$$ is constant, then the charge density giving rise to the above potential would be

A. zero

B. $$ - 6\,{\phi _0}{\varepsilon _0}$$

C. $$ - 2\,{\phi _0}{\varepsilon _0}$$

D. $$ - \frac{{6\,{\phi _0}}}{{{\varepsilon _0}}}$$

Answer: Option B


This Question Belongs to Engineering Physics >> Electromagnetic Theory

Join The Discussion

Related Questions on Electromagnetic Theory

Which one of the following current densities, $$\overrightarrow {\bf{J}} $$ can generate the magnetic vector potential $$\overrightarrow {\bf{A}} = \left( {{y^2}{\bf{\hat i}} + {x^2}{\bf{\hat j}}} \right)?$$

A. $$\frac{2}{{{\mu _0}}}\left( {x{\bf{\hat i}} + y{\bf{\hat j}}} \right)$$

B. $$ - \frac{2}{{{\mu _0}}}\left( {{\bf{\hat i}} + {\bf{\hat J}}} \right)$$

C. $$ - \frac{2}{{{\mu _0}}}\left( {{\bf{\hat i}} - {\bf{\hat j}}} \right)$$

D. $$\frac{2}{{{\mu _0}}}\left( {x{\bf{\hat i}} - y{\bf{\hat j}}} \right)$$