If the electrostatic potential were Igiven by $$\phi = {\phi _0}$$ (x2 + y2 + z2), where $${\phi _0}$$ is constant, then the charge density giving rise to the above potential would be
A. zero
B. $$ - 6\,{\phi _0}{\varepsilon _0}$$
C. $$ - 2\,{\phi _0}{\varepsilon _0}$$
D. $$ - \frac{{6\,{\phi _0}}}{{{\varepsilon _0}}}$$
Answer: Option B

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