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If the first term of an A.P. is a and nth term is b, then its common difference is
Answer & Solution
Correct Answer:
Option
B
In the given A.P.
First term = a and nth term = b
$$\eqalign{ & \therefore a + \left( {n - 1} \right)d = b \cr & \Rightarrow \left( {n - 1} \right)d = b - a \cr & \Rightarrow d = \frac{{b - a}}{{n - 1}} \cr} $$
First term = a and nth term = b
$$\eqalign{ & \therefore a + \left( {n - 1} \right)d = b \cr & \Rightarrow \left( {n - 1} \right)d = b - a \cr & \Rightarrow d = \frac{{b - a}}{{n - 1}} \cr} $$
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