If the nth term of an A.P. is 2n + 1, then the sum of first n terms of the A.P. is
A. n(n - 2)
B. n(n + 2)
C. n(n + 1)
D. n(n - 1)
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {a_n} = 2n + 1 \cr & {a_1} = 2 \times 1 + \,1 = 2 + 1 = 3 \cr & {a_2} = 2 \times 2 + 1 = 4 + 1 = 5 \cr & \therefore d = {a_2} - {a_1} = 5 - 3 = 2 \cr & \therefore {S_n} = \frac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right] \cr & = \frac{n}{2}\left[ {2 \times 3 + \left( {n - 1} \right) \times 2} \right] \cr & = \frac{n}{2}\left[ {6 + 2n - 2} \right] \cr & = \frac{n}{2}\left[ {2n + 4} \right] \cr & = n\left[ {n + 2} \right] \cr} $$Related Questions on Progressions
Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.
A. 5
B. 6
C. 4
D. 3
E. 7
The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
A. 600
B. 765
C. 640
D. 680
E. 690
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