If the potential difference between the ends of a conductor is doubled, what will be the effect on the current flowing in it?

This question relates to Ohm's Law, a fundamental principle in electricity.
Ohm's Law states: V = IR, where:
V is the potential difference (voltage).
I is the current.
R is the resistance.

The question says that the potential difference (V) is doubled. Let's say the initial potential difference was V1 and the initial current was I1. So, V1 = I1 * R.
Now the potential difference becomes V2 = 2 * V1.
Since the resistance (R) of the conductor remains constant, we can rewrite Ohm's Law for the new situation as:
2 * V1 = I2 * R, where I2 is the new current.

To find the relationship between I1 and I2, we can substitute V1 = I1 * R into the equation 2 * V1 = I2 * R:
2 * (I1 * R) = I2 * R

Divide both sides by R:
2 * I1 = I2

This means the new current (I2) is twice the original current (I1).

Therefore, the correct answer is: A: will be doubled