If the value of a is 0.9, then value of ß is ___________
A. 9
B. 0.9
C. 900
D. 90
Answer: Option D
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Related Questions on Transistors
In a transistor, signal is transferred from a ___________ circuit
A. high resistance to low resistance
B. low resistance to high resistance
C. high resistance to high resistance
D. low resistance to low resistance
In a transistor amplifier circuit VCE = VCB + ___________
A. VBE
B. 2 VBE
C. 5 VBE
D. None of the above

The answer is not option D but rather option A which is 9.
This is because the relationship between alpha and beta is : Beta = [ alpha / (1 - alpha)].
>> 0.9/(1-0.9)
0.9/0.1 =9
Correct answer is A which is 9
Answer is 9
As.. Beta = alpha/(1-alpha)
=0.9(1-0.9)
=0.9/0.1
=9
If the value of alpha is 0.9, then a per the relation between alpha and beta, shouldn't the answer be "9"?
Because beta = alpha/(1-alpha) is the relation and after calculation we get:
beta = 0.9/(1-0.9) = 0.9/0.1 = 9, which is the answer.
But while solve through formula of beta it comes out to be 9 not 90 can you explain how it becomes 90
But while it comes to be 9 then how it will 90