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Engineering Mechanics
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If two bodies having masses m1 and m2 (m1 > m2) have equal kinetic energies, the momentum of body having mass m1 is _________ the momentum of body having mass m2.

Answer & Solution
Correct Answer: Option C
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3 Comments
Rajan Mech
Rajan Mech 6 years ago
m1v1²=m2v2²
m1/m2=(V2/V1)²
m1/M2>1 so V2/V1 >1
Momentum ratio =m1v1/m2v2
Substitute m1/M2=(V2/V1)² in momentum ratio

Momentum ratio =(V2/V1)² ×(V1/V2)=V2/V1 which is greater than one
NIKHIL Kumar
NIKHIL Kumar 7 years ago
m1>m2
KE 1 = KE 2
m1v1² = m2v2²
(v2/v1) = √(m1/m2)
Momentum(p) = mv
KE = 0.5 mv² = 0.5 pv
p1 = ( v2/v1) p2
p1 √m2 =p2 √ m1
As m1>m2
p1
Harish Kumar
Harish Kumar 7 years ago
how explain