Examveda

If V = Vmsinωt is the voltage across the capacitor, then the current is:

A. $${I_m}\sin \left( {\omega t + \frac{\pi }{2}} \right)$$

B. $$\frac{{{I_m}}}{{\sqrt 2 }}$$

C. $${I_m}\sin \omega t$$

D. $${I_m}\sin \left( {\omega t - \frac{\pi }{2}} \right)$$

Answer: Option A


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