If x = 0.5 and y = 0.2, then the value of $$\sqrt {0.6} \times {\left( {3y} \right)^x}$$   is equal to?

Solution (By Examveda Team)

$$\eqalign{ & x = 0.5 \cr & y = 0.2 \cr & \sqrt {0.6} \times {\left( {3y} \right)^x}{\text{ }} \cr & = \sqrt {0.6} \times {\left( {3 \times 0.2} \right)^{0.5}}{\text{ }} \cr & = \sqrt {0.6} \times \sqrt {0.6} \cr & = 0.6 \cr} $$