If $$x + \frac{1}{x} = 8,$$ then find the value of $$\frac{{5x}}{{{x^2} + 1 - 6x}}.$$
A. 2.5
B. 6
C. 5
D. 6.5
Answer: Option A
Solution (By Examveda Team)
$$\eqalign{ & x + \frac{1}{x} = 8 \cr & {x^2} + 1 = 8x \cr & \frac{{5x}}{{{x^2} + 1 - 6x}} \cr & = \frac{{5x}}{{8x - 6x}} \cr & = \frac{{5x}}{{2x}} \cr & = \frac{5}{2} \cr & = 2.5 \cr} $$This Question Belongs to Arithmetic Ability >> Algebra
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