ExamVeda
Login
Home
This question belongs to Arithmetic Ability Algebra
Algebra
?

If $$x + \frac{1}{x} = 8,$$   then find the value of $$\frac{{5x}}{{{x^2} + 1 - 6x}}.$$

Answer & Solution
Correct Answer: Option A
$$\eqalign{ & x + \frac{1}{x} = 8 \cr & {x^2} + 1 = 8x \cr & \frac{{5x}}{{{x^2} + 1 - 6x}} \cr & = \frac{{5x}}{{8x - 6x}} \cr & = \frac{{5x}}{{2x}} \cr & = \frac{5}{2} \cr & = 2.5 \cr} $$
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.