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If $$x + \frac{1}{x} = 8,$$ then find the value of $$\frac{{5x}}{{{x^2} + 1 - 6x}}.$$
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& x + \frac{1}{x} = 8 \cr
& {x^2} + 1 = 8x \cr
& \frac{{5x}}{{{x^2} + 1 - 6x}} \cr
& = \frac{{5x}}{{8x - 6x}} \cr
& = \frac{{5x}}{{2x}} \cr
& = \frac{5}{2} \cr
& = 2.5 \cr} $$
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