?
If x = 3 + 2√2, then the value of $${x^2} + \frac{1}{{{x^2}}}$$ is:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& x = 3 + 2\sqrt 2 \cr
& \frac{1}{x} = 3 - 2\sqrt 2 \cr
& x + \frac{1}{x} = 6 \cr
& {x^2} + \frac{1}{{{x^2}}} = {\left( 6 \right)^2} - 2 \cr
& {x^2} + \frac{1}{{{x^2}}} = 34 \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login