If (x - 4)(x2 + 4x + 16) = x3 - p, then p is equal to?
A. 27
B. 8
C. 64
D. 0
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & {\text{We know that }} \cr & {a^3} - {b^3} = \left( {a - b} \right)\left( {{a^2} + ab + {b^2}} \right) \cr & {x^3} - p = \left( {x - 4} \right)\left( {{x^2} + 4x + 16} \right) \cr & \Rightarrow {x^3} - p = \left( {{x^3} - {4^3}} \right) \cr & \Rightarrow p = {4^3}{\text{ }}\left( {{\text{By comparison}}} \right) \cr & {\text{So, }}p = 64 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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