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If x = $$a + \frac{1}{a}$$ and y = $$a - \frac{1}{a}$$ then $$\sqrt {{x^4} + {y^4} - 2{x^2}{y^2}} $$ is equal to:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& x = a + \frac{1}{a},\,y = a - \frac{1}{a} \cr
& {\text{Let}} \Rightarrow a = 1 \cr
& x = 1 + \frac{1}{1} = 2 \cr
& y = 1 - 1 = 0 \cr
& \sqrt {{x^4} + {y^4} - 2{x^2}{y^2}} \cr
& = \sqrt {16 + 0 - 0} \cr
& = 4 \cr} $$
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