If $$x + \frac{1}{x} = 1,$$   then the value of $$\frac{2}{{{x^2} - x + 2}} = \,?$$

A. $$\frac{2}{3}$$

B. 2

C. 1

D. 4

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{Given, }}x + \frac{1}{x} = 1 \cr & {\text{Find }}\frac{2}{{{x^2} - x + 2}} = ? \cr & x + \frac{1}{x} = 1 \cr & {x^2} + 1 = x \cr & \left( {{x^2} - x} \right) = - 1 \cr & {\text{Putting value in,}} \cr & = \frac{2}{{{x^2} - x + 2}} \cr & = \frac{2}{{ - 1 + 2}} \cr & = 2 \cr} $$