If $$x + \frac{1}{x} = 2{\text{,}}$$ then the value of $${x^{12}} - \frac{1}{{{x^{12}}}}$$ is?
A. -4
B. 4
C. 2
D. 0
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & {\text{Given, }}x + \frac{1}{x} = 2\ , . . . . . . (i) \cr & {\text{The value of }}{x^{12}} - \frac{1}{{{x^{12}}}} =\, ? \cr & \Rightarrow {\text{If }}x = 1 \cr & \Rightarrow x + \frac{1}{x} = 2 \cr & \Rightarrow 1 + 1 = 2 \cr & {\text{Then, }}{x^{12}} - \frac{1}{{{x^{12}}}} \cr & \Rightarrow {1^{12}} - \frac{1}{{{1^{12}}}} \cr & \Rightarrow 1 - 1 \cr & \Rightarrow 0 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
Join The Discussion