If $$x + \left( {\frac{1}{x}} \right) = 2{\text{,}}$$ then the value of $${x^7}{\text{ + }}\left( {\frac{1}{{{x^5}}}} \right)$$ is?
A. 25
B. 212
C. 2
D. 27
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & x + \frac{1}{x} = 2 \cr & {\text{Find , }}{x^7} + \frac{1}{{{x^5}}} \cr & \,\,\,\,\,\,\,x + \frac{1}{x} = 2 \cr & \Rightarrow \mathop \downarrow \limits_1 {\text{ }}\,\,\,\,{\text{ }}\mathop \downarrow \limits_1 \,\,\,\,\,\,\,\,\,\,\,\,\,\, \Rightarrow {\text{Let }}x = 1 \cr & {\text{To put value in question,}} \cr & \Rightarrow {x^7} + \frac{1}{{{x^5}}} \cr & \Rightarrow {{\text{1}}^7} + \frac{1}{{{1^5}}} \cr & \Rightarrow 1 + 1 \cr & \Rightarrow 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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