?
If $$x + \frac{1}{{9x}} = 4{\text{,}}$$ then $${\text{9}}{x^2} + \frac{1}{{9{x^2}}}$$ is?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& {\text{ }}x + \frac{1}{{9x}} = 4 \cr
& {\text{Multiply by 3 both side}} \cr
& \Rightarrow {\text{3}}x + \frac{1}{{3x}} = 12 \cr
& {\text{Squaring both sides}} \cr
& \Rightarrow {\text{9}}{x^2} + \frac{1}{{9{x^2}}} + 2 \times 3x \times \frac{1}{{3x}} = 144 \cr
& \Rightarrow {\text{9}}{x^2} + \frac{1}{{9{x^2}}} + 2 = 144 \cr
& \Rightarrow {\text{9}}{x^2} + \frac{1}{{9{x^2}}} = 142 \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login