If $$x + \frac{1}{x} = 2$$ then $${x^2} + \frac{1}{{{x^2}}}$$ is equal to?
A. 0
B. 2
C. 4
D. 8
Answer: Option B
Solution (By Examveda Team)
$$\eqalign{ & x + \frac{1}{x} = 2{\text{ }} \cr & {\text{But }}x = 1 \cr & {\text{So, }}{x^2} + \frac{1}{{{x^2}}} = {1^2} + \frac{1}{{{1^2}}} = 2 \cr} $$Related Questions on Algebra
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$

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