If $$x = {\left( {0.25} \right)^{\frac{1}{2}}},$$ $$y = {\left( {0.4} \right)^2},$$ $$z = {\left( {0.216} \right)^{\frac{1}{2}}}$$ then-
A. y > x > z
B. x > y > z
C. z > x > y
D. x > z > y
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & x = {\left( {0.25} \right)^{\frac{1}{2}}} \cr & x = \root 2 \of {0.25} = 0.5{\text{ }} \cr & y = {\left( {0.4} \right)^2} \cr & y = 0.16 \cr & z = {\left( {0.216} \right)^{\frac{1}{2}}} \cr & z = \root 2 \of {0.216} = 0.464 \cr & \therefore x > z > y \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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