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If $$x \ne 0,$$ $$y \ne 0$$ and $$z \ne 0$$ and $$\frac{1}{{{x^2}}}$$ + $$\frac{1}{{{y^2}}}$$ + $$\frac{1}{{{z^2}}}$$ = $$\frac{1}{{xy}}$$ + $$\frac{1}{{yz}}$$ + $$\frac{1}{{zx}}$$ then the relation among x, y, z is?
Answer & Solution
Correct Answer:
Option
D
$$\frac{1}{{{x^2}}} + \frac{1}{{{y^2}}} + \frac{1}{{{z^2}}} = \frac{1}{{xy}} + \frac{1}{{yz}} + \frac{1}{{zx}}$$
Go through option D take x = y = z
$$\eqalign{ & \frac{1}{{{x^2}}} + \frac{1}{{{x^2}}} + \frac{1}{{{x^2}}} = \frac{1}{{x^2}} + \frac{1}{{x^2}} + \frac{1}{{x^2}} \cr & \therefore {\text{Option 'D' is right}} \cr} $$
Go through option D take x = y = z
$$\eqalign{ & \frac{1}{{{x^2}}} + \frac{1}{{{x^2}}} + \frac{1}{{{x^2}}} = \frac{1}{{x^2}} + \frac{1}{{x^2}} + \frac{1}{{x^2}} \cr & \therefore {\text{Option 'D' is right}} \cr} $$
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